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  • What’s the difference between EAX, EBX, and ECX in assembly?
    eax, ebx, ecx and so on are actually registers, which can be seen as "hardware" variables, somewhat similar to higher level-language's variables Registers can be used in your software directly with instructions such as mov, add or cmp
  • What does the bracket in `movl (%eax), %eax` mean?
    MOV sets EAX = the value from memory at that address Your re-phrasing of the existing answer isn't adding anything new, and is actually less clear because you're mis-using "address" to mean "memory at that address", which is the opposite of what "address" normally means
  • Dashboard EAX - Forex Factory
    Latest EAX update (on a fresh setup install prerequisites first) Inserted Code DBMASMEAX007a3 bundle3 rev update 013 7 5 (20220615): …expiring in 2023 12 31 23:59:59 GMT !
  • c - Why is eax used on 64-bit? - Stack Overflow
    %eax refers to the lower 32 bits of the 64-bit %rax register So, if %rax is initially 0, and you execute the instruction movl $5, %eax, then %rax will also take on the value 5 However, they are not entirely independent, so one should be careful
  • Why would one use movl $1, %eax as opposed to, say, movb $1, %eax
    %eax is not zeroed out unless you either movl $0, %eax, or if you xorl %eax, %eax Otherwise it holds whatever value was previously in there When you movl $1, %eax, you will end up with 0x00000001 in the register because the 32-bit instruction moves a 32-bit immediate value into the register
  • assembly - The point of test %eax %eax - Stack Overflow
    TEST EAX,EAX JE some_address the CPU will jump to "some_address" if and only if ZF = 1, in other words if and only if AND(EAX,EAX) = 0 which in turn it can occur if and only if EAX == 0 the equivalent C code is:
  • x86 - imul assembly instruction - one operand? - Stack Overflow
    In your case with imul edx, you get EDX:EAX = EAX * EDX It's fine for the explicit source operand to be one of the implicit operands, even EAX to square into EDX:EAX If you only want the low 32 bits of the result, use the 2-operand form of imul ; it runs faster and doesn't have any implicit operands (so you can use whatever registers are
  • xv6: what does `popl 0(%eax)` mean? (OSTEP) - Stack Overflow
    I understand that movl 4(%esp), %eax moves the content inside the address 4(%esp) (first parameter of the method, or the old context address) to register eax However, the next line popl 0(%eax) seems to also pop from the stack (which points to the instruction pointer of the caller) and load it into eax
  • Assembly registers in 64-bit architecture - Stack Overflow
    hmm eax == 32bits ax == 16bits ah|al == 8bits, it's always like this, x64 adds new registers, back in the 16 bit days we only had ax al ah then when 32 bit addressing came round it was added in a way that didn't really effect how you address the 16bit or 8bit registers, the new registers in x64 (64 bit registers that overlap, eax that overlaps ax, etc) start with an r so rax rbx and so on





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